A flask is filled with 1.3 g of an ideal gas at `27^@C` and its temperature is raised to `52^@C`. The mass of the gas that has to be released to maintain the temperature of the gas in the flask at `52^@C` and the pressure remaining the same is

Options

A. 2.5g
B. 20g
C. 1.5g
D. 0.1g

Answer

D

Explanation

`1/(m_(1)T_(1)) = 1/(m_(2)T_(2))` [`because P_(1)=P_(2)`]
`therefore m_(2) = (1.3xx300)/325 = 1.2`
Gas to be removed = 1.3-1.2 = 0.1g