A wire whose cross-sectional area is `2 mm^2` is stretched by 0.1 mm by a certain load. If a similar wire of triple. the area of cross-section is stretched by the same load, the elongation of the second wire would be

Options

A. 0.33mm
B. 0.033mm
C. 3.3mm
D. 0.0033mm

Answer

B

Explanation

Change in length, `Deltal = (Fl)/(AE)`
`(Deltal_(1))/(Deltal_(2))` [Material is same, E is same and also as wire are similar l is same]
`implies 0.1/(Deltal_(2)) = F_(1)/F_(2) xx 6/2` [`because F_(1)=F_(2)`]
`Delta l_(2)=0.1/3 = 0.033 mm`