A uniform chain of length L is lying on the horizontal table.If the coefficient of friction between the chain and table top is m, what is the maximum length of the chain that can hang over the edge of the table without disturbing the rest of the chain on the table?

Options

A. `L/((1+mu))`
B. `muL/((1+mu))`
C. `muL/((1+mu))`
D. `muL/((1-mu))`

Explanation

Velocity of centre of mass,
`V_(cm)=(m_1v_1+m_2v_2)/(m^1+m^2)=((4)(5hati)+(2)(10hati))/(4+2)=(40hati)/6`