The horizontal and vertical displacements x and y of a projectile at a given time t are given by x = 6t metre and `y = 8t-5t^2` metre. The range of the projectile in metre is

Options

A. 9.6
B. 10.6
C. 19.2
D. 38.4

Explanation

Comparing `x=36t` with `x=(ucostheta)`and `y=96t-9.8t^2`with`y=(usintheta)t-1/2g t^2` then,
`impliesucostheta=36,u=sintheta=48`
`implies(usintheta)/(ucostheta)=(48)/(36)`
`impliestantheta=4/3`
`impliessintheta=4/5`
`:.theta=sin^(-1)(4/5)`