The equations of motion of a projectile are given by x = 36t inetre and 2y = `96t -9.8t^2` metre. The angle of projection is

Options

A. `sin^(-1)(4/5)`
B. `sin^(-1)(3/5)`
C. `sin^(-1)(4/3)`
D. `sin^(-1)(3/4)`

Explanation

Consider a point 'A'on the surface of the hemisphere,where the body leaves the surface.
At point A, `mgcostheta-N=(mv^2)/r`
when the body leaves the surface ,N=0.
`impliesmgcostheta=(mv^2)/r`
`impliescostheta=v^2/(rg)=5^2/5xx10=1/2`
`:. theta=60^(@)`.