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The horizontal and vertical displacement...

The horizontal and vertical displacements of a projectile at time t are `x = 36t and y = 48t -4.9t^2` respectively. lmtial velocity of the projectile in `ms^-1` is

A

15

B

30

C

45

D

60

Text Solution

Verified by Experts

Comparing`h=Ax-Bx^2`with standrad equation of trajectory,
`h=xtantheta-(gx^2)/(2u^2cos^2theta)` then,
`impliesA=tantheta=tan45^0=1`
`B=g/(2u^2cos^2theta)=10/(2xx20^2xxcos^2 45^(@))=0.025`
`A/B=1/0.025= 40/1`
`A:B=40:1`
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