The speed of a projectile at its maximum height is `sqrt3/2` times its initial speed. If the range of the projectile is P times the maximum height attained by it, then P equals

Options

A. `4/3`
B. `2 sqrt3`
C. `4 sqrt3`
D. `3/4`

Explanation

`H=1/2g t^2`
`implies5=1/2xx10xx t^2`
`t=1s`
`:.` Total time for the fifth drop to fall on the ground =1s.
Time taken by the second drop to fall an ground `=t/4=1/34=0.25`
Time taken by the third drop to fall on ground `=0.25+0.25=0.5s`
`:`.The height covered by third drop
`H=1/2xx10xx (0.52)^2=1.25m.`