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A body falling for 2 s covers a distance...

A body falling for 2 s covers a distance a which is equal to that covered in next l s. If `g = 10 ms^ -2`, the distance s is

A

30 m

B

10 m

C

60 m

D

20 m

Text Solution

Verified by Experts

Tension in string ,`T=mv^2/r+mgcostheta`
At lowest position, `theta=0^0`
`impliesT=(mv_2)/r+mgcos0^0`
`T=(mv^2)/r+mg`
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