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A 2 kg stone tied at the end of a string...

A 2 kg stone tied at the end of a string of l m len"gt"h, is whirled along a vertical circle at a constant speed of `4 ms^-1`. The tension in the string has a value of 52 N when the stone is

A

At the top of the circle

B

Halfway down

C

At the bottom of the circle

D

None of the above

Text Solution

Verified by Experts

Distance travelled in `n^(th)`second,
`s_n=u+1/2a(2n-1)`
Distance covered by the first body in `5^(th)` second
`s_1=0+1/2xxa_1xx(10-1)=9/2a_1`
Distance covered by the second body
`s_2=(0+1)/(2)xxa_2xx((2xx3)-1)`
`=5/2a_2`
Since,`s_1=s_2`
`implies9/2a_1=5/2a_2`
`impliesa_1/a_2=5/9`
`:.a_1:a_2=5:9`
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