The banking angle for a curved road of radius 490 m for a vehicle moving at `35 ms^-1` is

Options

A. `tan^-1 (0.25)`
B. `tan^_1 (0.55)`
C. `tan^_1 (0.45)`
D. `tan^-1(0.75)`

Explanation

We know that,
Banking angle,`theta =(tan^-1)(v^2)/(rg)`
`tantheta=v^2/(rg)`
Given that ,`'theta'`is same, so `v_2 prop r`
`((v_1)/v_2)^2=r^1/r^2`
`(v+(10v)/100)^2/v^2=r_1/r_2`
`r_2=r_1**v^2/((11/10)^2v^2)`
`=121/100**20`
`r_2=24.2m`