A body falling from rest has a velocity v after it falls through a distanc.e h. The distance it has to fall down further, for its velocity to become double, is ..... times h

Options

A. 5 h
B. h
C. 5 h
D. 3 h

Explanation

`v_1=v,h_1=h,R_1=250m,m_1=m`
`v_2=v/2,h_2=4h,R_2=?,m_2=2m`
Time taken ,`t=((sqrt2h)/(g))impliestpropsqrth`Range,R=velocityTime
`R_1/R_2=(v_1)/(v_2)xx(t_1)/(t_2)``impliesR_1/R_2=v/((v)/(2))xxsqrt(h_1/h_2`
`implies250/(R_2)=2xxsqrt((h)/(4h))`
`:.R_2=250m`