[a^(2)-8],[" 18."(3x)/(3x+2)=(1)/(2)]

(3x-8)/(2)x=1

Find the term independent of x (constant term) in the following expansion: (i) (x^(2)-(1)/(3x))^(9) " "(ii) (x-(1)/(x))^(10) (iii) (3x-(2)/(x^(2)))^(18) " "(iv) (1)/(x^(n))(1+x)^(2n) (V)(3sqrt(x)+(1)/(2(3sqrt(x))))^(18)" "(vi)((3x^(2))/(2)-(1)/(3x))^(6)

3x=2x+18

x^(3)-(1)/(x^(3)) if "x^(2)+(1)/(x^(2))=18

1<(3x^(2)-7x+8)/(x^(2)+1)<2

Resolve (2x^(2)+3x+18)/((x-2)(x+2)^(2)) into partical fractions.

1<(3x^(2)-7x+8)/(x^(2)+1)<=2

Evaluate : -7x^(2) + 18x^(2) + 3x^(2) - 5x^(2)