" 56."(cos x)/(log_(a)x)

(cos x)/("log"_(e)x)

If x in(0,(pi)/(2))-{1,(pi)/(4)} then the expression (log_(cos x)(x)*log_(tan x)(x))/(log_(cos x)(x)+log_(tan x)(x)) simplifies to

lim_(x rarr 0) (log_(sec x//2) cos x)/(log_(sec x)cos x//2) is equal to :

lim_(x=0)(log_(sin x)cos x)/(log_(sin((x)/(2)))cos((x)/(2)))

lim_(x rarr0)((log_(sec(x/2))cos x)/(log_(sec x)cos((x)/(2))))=

log_(10)sin x+log_(10)cos x=-1 and log_(10)(sin x+cos x)=((log_(10)n)-1)/(2) then the value of 'n/3' is

If log_(10)sin x + log_(10)cos x=-1 and log_(10)(sin x + cos x)=((log_(10)n)-1)/(2) , then the value of 'n//3' is ......

lim_(x rarr oo)(1+((log cos x)/(log cos((x)/(2))))^(2))^(2)

Differentiate : (log(cos x))/(tan(log x))