The output of a step-down transformer is measured to be `24 V` when connected to a 12 watt light bulb. The value of the peak current is

Options

A. `1//sqrt(2)A`
B. `sqrt(2)A`
C. 2A
D. `2sqrt(2)`A

Answer

A

Explanation

secondary voltage `V_(S) = 24V`
Power associated with secondary `P_(S) =12 W`
`I_(s)=P_(S)/V_(s)=12/24`
`=1/2A=0.5A`
Peak value of the current in the secondary
`I_(0) = I_(S) sqrt(2)`
`=(0.5)(1.414)=0.707=1/sqrt(2)A`