In series LCR circuit, the plot of `I_("max")` versus `omega` is shown in figure. Find the bandwidth and mark in the figure.

Answer

A

Explanation

consider the diagram.
Bandwith`=omega_(2)-omega_(1)`

when `omega_(1)` and `omega_(2)` corresponds to frequency at which magnitude of current is `1/sqrt(2)` times of maximum value.
`I_("rms") = I_("max")/sqrt(2) = 1/sqrt(2)=0.7A`
Clearly from the diagram, the coresponding frequencies are 0.8 rad/s and 1.2 rad/s.
`Deltaomega=` Bandwith `=1.2 -0.8=0.4` rad/s