A variable frequency AC source is connected to a capacitor. How will the displacement current change with decrease in frequency?

Explanation

Capacitive reaction `X_(c) =(1)/(2pifC')`
`:. " " X_(c) prop (1)/(f)`
As frequency decreases `X_(c)` increases and the conduction current is inversely proportional to `X_(c) (":." I prop (1)/(X_(c)))`
So displacement current decreases as the conduction current is equal to the displacement current.