You are given a `2mu F` parallel plate capacitor. How would you establish an instantaneous displacement current fo 1mA in the space between its plates?

Explanation

Given , capacitance of capapcitor `C= 2mu F`
Displacement current `I_(d) 1 mA`
`"Charge"" "q=CV" "[":." q=it]`
`I_(d)dt =CdV`
`" or "" "I_(d) =C (dV)/(dt)`
`1xx10^(-3) =2 xx 10^(-6) xx (dV)/(dt)`
`" or "" "(dV)/(dt) =1/2 xx 10^(+3) = 500 V//s`
So, by applying a varying potential difference of `500V//s`we would produce a displacement current of desired value.