In the Angular process as atom makes a transition to a lower state without emitting a photon. The excess energy is transferred to an outer electron which may be ejected by the atom. (this is called an Augar elecrons ) . Assuming the nuclesu to be massive , calculate the kinetic energy of an `n=4` Augar electron emitted by chromium by absorbing the energy from a `n=2` to `n=1` transition .

Explanation

The energy of the nth state `E_(n) = - Z^(2)R(1)/(n^(2))` where R is the Rydberg constant and Z = 24.
The energy released in a transition from 2 to 1 is `DeltaE = Z^(2)R(1-(1)/(4)) = (3)/(4)Z^(2)R`.
The energy required to eject a `n = 4` electron is `E_(4) = Z^(2)R (1)/(16)`
Thus, the kinetic energy of the Augar electron is
`KE = Z^(2)R((3)/(4) - (1)/(16)) = 1/(16)Z^(2)R`
`= (11)/(16) xx 24 xx 24 xx 13.6eV`
`= 5385.6eV`