[x+2y+4z=12],[y+2z=-1],[3x+2y+4z=4]

2x+y+z=1x-y+2z=-1,3x+2y-z=4

The solution of 2x+y+z=1,x-2y-3z=1,3x+2y+4z=5 is

Prove the identities: |[z, x, y],[ z^2,x^2,y^2],[z^4,x^4,y^4]|=|[x, y, z],[ x^2,y^2,z^2],[x^4,y^4,z^4]|=|[x^2,y^2,z^2],[x^4,y^4,z^4],[x, y, z]| =x y z (x-y)(y-z)(z-x)(x+y+z)

Prove the identities: |[z, x, y],[ z^2,x^2,y^2],[z^4,x^4,y^4]|=|[x, y, z],[ x^2,y^2,z^2],[x^4,y^4,z^4]|=|[x^2,y^2,z^2],[x^4,y^4,z^4],[x, y, z]| =x y z (x-y)(y-z)(z-x)(x+y+z)

Solve: 2x-y+z=4,x+3y+2z=12,3x+2y+3z=16

Solve : 2x-y+z=4 , x+3y+2z=12 , 3x+2y+3z=16

Solve : x+y+z =1, 2x+2y+2z=3, 3x+3y+3z=4

Solve the following system of linear equations by matrix method : 2x - 3y + 5z = 1 1 , 3x + 2y - 4z = - 5, x + y - 2z = - 3

Solve x+y+z=1 , 2x+2y+2z=2 , 3x+3y+3z=4