The `6^("th")` term of expansion `[sqrt(2^(log_(10)(10-3^(x))))+root(5)(2^((x-2)log_(10)3))]^(m)` is 21 and the coefficient of `2^(nd), 3^(rd) and 4^(th)` terms of it are respectively `1^(st), 3^(rd) and 5^(th)` term of an A.P. Find x.

If the coefficients of 2^(nd),3^(rd) and 4^( th ) terms in expansion of (1+x)^(n) are in A.P then value of n is

The sixth term in the expansion of ( sqrt(2^(log(10-3^x))) + (2^((x-2)log3))^(1/5))^m is equal to 21, if it is known that the binomial coefficient of the 2nd 3rd and 4th terms in the expansion represent, respectively, the first, third and fifth terms of an A.P. (the symbol log stands for logarithm to the base 10) The value of m is

If the 3^(rd) and the 9^(th) terms of an A.P. are 4 and -8 respectively ,which term of thi A.P. is zero ?

In a G.P.sum of 2^(nd),3^(rd) and 4^(th) term is 3 and that 6^(th),7^(th) and 8^(th) term is 243 then S_(50)=

If the 3rd and 7th terms of an A.P. are 17 and 27 respectively . Find the first term of the A.P.:

If the coefficients of 5^(th), 6^(th) and 7^(th) terms in the expansion of (1+x)^(n) are in A.P. then n =

If the coefficients of 2nd,3rd and 4th terms in the expansion of (1+x)^(n) are in A.P.then find the value of n.

If the coefficients of 2nd,3rd and 4th terms in the expansion of (1+x)^(n) are in A.P.then find the value of n.