" The system of equations "2x+py+6z=8,x+2y+qz=5,x+y+3z=4" will have no solution if "

For what values of p and q the system of equations 2x+py+6z=8, x+2y+qz=5, x+y+3z=4 has (i) no solution (ii) a unique solution (iii) in finitely many solutions.

For what value of p , system of equations 2x + py = 8 and x + y = 6 have no solution.

If the system of equations 2x+ay+6z=8, x+2y+z=5, 2x+ay+3z=4 has a unique solution then 'a' cannot be equal to :

The values of a and b, for which the system of equations 2x+3y+6z=8 x+2y+az=5 3x+5y+9z=b has no solution ,are :

For what values of a and b, the system of equations 2x+ay+6z=8x+2y+bz=5x+y+3z=4 has: (i) a unique solution (ii) infinitely many solutions no solution

The system of equations x+2y +3z =4, 2x+3y+4z=5,3x+4y+5z=6 has