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The statement (p vv ~q)rArr p is logical...

The statement `(p vv ~q)rArr p` is logically equivalent to

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The incorrect statement is p rarr q is logically equivalent to -p vv q. If the truth-values of p,qr are T,F,T respectively,then the truth value of (p vv q)^^(q vv r) is T .sim(p vv q vv r)-=sim p^^sim q^^sim r The truth value of p^^sim(p^^q) is always T.