Consider two positive numbers a and b. If arithmetic mean of a and b exceeds their geometric mean by 3/2, and geometric mean of aand b exceeds their harmonic mean by 6/5 then the value of `a^2+b^2` will be

The arithmetic mean of two numbers exceeds their geometric mean by 2 and the geometric mean exceeds their harmonic mean by 1.6. What are the two numbers ?

If a is a positive number such that the arithmatic mean of a and 2 exceeds their geometric mean by 1. Then, the value of a is

Let a be a positive number such that the arithmetic mean of a and 2 exceeds their geometric mean by 1. Then the value of a

Let a be a positive number such that the arithmetic mean of a and 2 exceeds their geometric mean by 1. Then, the value of a is

The arithmetic mean of two positive numbers a and b exceeds their geometric mean by (3)/(2) and the geometric mean exceeds their harmonic mean by (6)/(5) . If a+b=alpha and |a-b|=beta, then the value of (10beta)/(alpha) is equal to

The arithmetic mean of two positive numbers a and b exceeds their geometric mean by (3)/(2) and the geometric mean exceeds their harmonic mean by (6)/(5) . If a+b=alpha and |a-b|=beta, then the value of (10beta)/(alpha) is equal to

Find two number whose arithmetic mean is 5 and the geometric mean is 4.