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If An=int0^(pi/2)(sin(2n-1)x)/(sinx)dx ...

If `A_n=int_0^(pi/2)(sin(2n-1)x)/(sinx)dx ;B_n=int_0^(pi/2)((sinn x)/(sinx))^2dx ;forn in N ,` then `A_(n+1)=A_n` (b) `B_(n+1)=B_n` `A_(n+1)-A_n=B_(n+1)` (d) `B_(n+1)-B=A_(n+1)`

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If A_n=int_0^(pi/2)(sin(2n-1)x)/(sinx)dx ,B_n=int_0^(pi/2)((sinn x)/(sinx))^2 dx for n inN , Then (A) A_(n+1)=A_n (B) B_(n+1)=B_n (C) A_(n+1)-A_n=B_(n+1) (D) B_(n+1)-B_n=A_(n+1)

If A_n=int_0^(pi/2)(sin(2n-1)x)/(sinx)dx ,B_n=int_0^(pi/2)((sinn x)/(sinx))^2 dx for n inN , Then (A) A_(n+1)=A_n (B) B_(n+1)=B_n (C) A_(n+1)-A_n=B_(n+1) (D) B_(n+1)-B_n=A_(n+1)

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