If `I = int((x+x^(2/3)+x^(1/6))/(x(1+x^(1/3)))) = Ax^B+C *arc tan x^D +k`,then (1) AB = 1,(2) CD = 1,(3) `A - B = 0`,(4)` C + D = 0`

int(x+x^(2/3)+2x^(1/6))/(x(1+x^(1/3)))dx=A*x^(2/3)+B tan^(-1)(x^(1/6))+c, then (i) A=(3)/(2),( ii) B=12, (iii) A=(2)/(3), (iv) B=(1)/(6)

If int (x^(4) + 1)/(x^(6) + 1) dx = A tan^(-1) x + B tan^(-1) x^(3) + c , then (A,B) =

int ((tan^(-1) x )^(3))/( 1+x^(2)) dx is equal to a) 3 ( tan^(-1) x )^(2) +C b) (1)/(4) ( tan^(-1)x)^(4) +C c) ( tan^(-1) x)^(4) + C d) none of these

If int ((3x^(2)+2x)dx)/(x^(6)+2x^(5)+x^(4)+2x^(3)+2x^(2)+5) = 1/A tan^(-1) ((x^(B)+x^(2)+c)/D)+l then A+B + C +D =

int(x^(2)+3)/(x^(6)(x^(2)+1))dx=-(a)/(x)+(b)/(3x^(3))-(d)/(5x^(5))-2tan^(-1)x+c

int(x+x^(2/3)+x^(1/6))/(x(1+x^(1/3)))dx equals a) (3x^(2/3))/(4)+6tan^(-1)(x^(1/6))+C b) (3x^(2/3))/(2)+6tan^(-1)(x^(1/6))+C c) (3x^(2/3))/(10)+6tan^(-1)(x^(1/6))+C d) (3x^(2/3))/(5)+6tan^(-1)(x^(1/6))+C

If x+a is a factor of x^4-a^2x^2+3x-6a , then a= (a) 0 (b) -1 (c) 1 (d) 2

If (1)/(x^(4)+x^(2)+1)=(Ax+B)/(x^(2)+x+1)+(Cx+D)/(x^(2)-x+1) then C+D

If (1)/(x^(4)+x^(2)+1)=(Ax+B)/(x^(2)+x+1)+(Cx+D)/(x^(2)-x+1) then C+D=