The value of `alpha`, which satisfy `int_(pi/2) ^(alpha) sin x dx = sin2alpha (alpha in [0,2pi]` are equal

The value of alpha in [0,2pi] which does not satify the equation int_(pi//2)^(alpha) sin x dx = sin 2 alpha, is

The value of alpha in [0,2pi] which does not satify the equation int_(pi//2)^(alpha) sin x dx = sin 2 alpha, is

If 0 le alpha le 2pi and int_(0)^(alpha)cos x dx = cos 2alpha , the : alpha =

The value of alpha in (-pi, 0) satisfying sin alpha+int_(alpha)^(2alpha) cos2 x dx=0 , is

int_(0)^(pi)( x dx)/(1+cos alpha sin x)[0 lt alpha lt pi]

The value of int_(0)^((pi)/(2))sin|2x-alpha|dx, where alpha in[0,pi], is