[sqrt(1+2cot x(cot x+cos ecx))dx=A log_(0)gx]],[" then "A=quad [0

int sqrt(1+2cot x(cot x+cos ecx))dx

sqrt(1+2cot x(cos ecx+cot x))dx=

3tan x+cot x=5cos ecx

int sqrt(1 + 2 cot x ( cot x + cosecx ) ) dx =

int x cos ecx cot xdx=

If int_(0)^( pi/2)(cot x)/(cot x+cos ecx)dx=m(pi+n) then m*n is equal to :

(cos ec x+cot x)/(cos ecx-cotx)

int sqrt(1+2cot x(cot x+cos ecx))dx is equal to (A) 2In((cos x)/(2))+c(B)2ln(s in(x)/(2))+c(C)(1)/(2)ln((cos x)/(2))+c(D)(1)/(2)ln(s in(x)/(2))+c

int e^(cot x)(cos x-cos ecx)dx is equal to :

int cos ecx log(cos ecx-cot x)dx