If a ray travelling the line x = 1 gets reflected the line `x+y=1` then the equation of the line along which the reflected ray travels is

If a ray travelling along the line x = 1 gets reflected from the line x + y = 1, then the eqaution the line along which the reflected ray travels is

A ray of light travels along a line y=4 and strikes the surface of curves y^(2)=4(x+y) . Then the equations of the line along which of reflected ray travels is x=0 (b) x=2 (c) x+y(d)2x+y=4

A ray of light travels along a line y=4 and strikes the surface of curves y^2=4(x+y)dot Then the equations of the line along which of reflected ray travels is x=0 (b) x=2 (c) x+y (d) 2x+y=4

A ray of light travels along a line y=4 and strikes the surface of curves y^2=4(x+y)dot Then the equations of the line along which of reflected ray travels is (a) x=0 (b) x=2 (c) x+y (d) 2x+y=4

A ray of light travels along a line y=4 and strikes the surface of curves y^2=4(x+y)dot Then the equations of the line along which of reflected ray travels is x=0 (b) x=2 (c) x+y (d) 2x+y=4

A ray of light travels along a line y=4 and strikes the surface of curves y^2=4(x+y)dot Then the equations of the line along which of reflected ray travels is x=0 (b) x=2 (c) x+y (d) 2x+y=4

A ray of light travels along a line y=4 and strikes the surface of curves y^2=4(x+y)dot Then the equations of the line along which of reflected ray travels is x=0 (b) x=2 (c) x+y (d) 2x+y=4

A ray of light along the line x-2y+5=0 is reflected from the line 3x-2y+7=0.Fidn the equations of the line containing the reflected ray.

A ray of light along the line x- 2y + 5 = 0 is reflected from the line 3x - 2y + 7= 0 . Find the equation of the line containing the reflected ray .

A ray of light is sent along the line 2x-3y=5. After refracting across the line x+y=1 it enters the opposite side after torning by 15^0 away from the line x+y=1 . Find the equation of the line along which the refracted ray travels.