If sum(r=m)^n ^rCm=^(n+1)C(m+1), then s...

If `sum_(r=m)^n ^rC_m=^(n+1)C_(m+1)`, then `sum_(r=m)^n (n-r+1)^rC_m` is equal to `sum_(r=m)^n (n-r+1)^rC_m` is equal to

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