Find the angle between the two planes `3x - 6y + 2z = 7`and `2x + 2y - 2z =5`.

Explanation

To find the angle between the two planes given by the equations \(3x - 6y + 2z = 7\) and \(2x + 2y - 2z = 5\), we can follow these steps:

### Step 1: Identify the Normal Vectors of the Planes
The equation of a plane in the form \(Ax + By + Cz = D\) has a normal vector \(\mathbf{n} = (A, B, C)\).

- For the first plane \(3x - 6y + 2z = 7\), the normal vector \(\mathbf{n_1} = (3, -6, 2)\).
- For the second plane \(2x + 2y - 2z = 5\), the normal vector \(\mathbf{n_2} = (2, 2, -2)\).

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