The mean and variance of a binomial distribution are `4` and `frac{4}{3}` respectively, find `P(Xgeq1)`

Explanation

To solve the problem, we need to find \( P(X \geq 1) \) for a binomial distribution where the mean is 4 and the variance is \( \frac{4}{3} \).

### Step-by-Step Solution:

1. **Understand the Mean and Variance of Binomial Distribution**:
- For a binomial distribution, the mean \( \mu \) is given by:
\[
\mu = n \cdot p
...