A particle is moving in a circular path ...

A particle is moving in a circular path of radius r. The displacement after half a circle would be

zero

`pi`r

`2pi` r

Text Solution

Verified by Experts

The correct Answer is:

Given, aftar half the circle, the particle will reach the diametrically opposite opint i.e., from point A to point B. And we know displacement is shortest path between initial and final point.
`:.` Displacement after half circle = AB = OA + OB [`because` Given , OA and OB = r]

= r + r = 2r
Hence, the displacement aftar half circle is 2r.

Topper's Solved these Questions

MOTION
NCERT EXEMPLAR|Exercise Short Answer Type Questions|1 Videos
GRAVITATION
NCERT EXEMPLAR|Exercise Gravitation|26 Videos
SOUND
NCERT EXEMPLAR|Exercise Sound|20 Videos

A particle moves along a circular path of radius R. The distance and displacement of a particle after one completer revolution is

`0, 2 pi r`

`2 pi r, 0`

`0, pi r`

`pi r, 0`

A particle moves along a circular path of radius R. The distance and displacement of the particle after one complete revolution is

`0,2pir`

`2pir, 0`

`0,pi r`

`pir, 0`

A particle is moving in a circular path of radius a under the action of an attractive potential U=-(k)/(2r^(2)) . Its total energy is :

`-(3)/(2)(k)/(a^(2))`

`-(k)/(4a^(2))`

`(k)/(2a^(2))`

Zero