A motorcyclist drives from `A` to `B` with a uniform speed of `30 km h^(-1)` and returns back with a speed of `20 kmh^(-1)`. Find its average speed.
Text Solution
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Let the distance between A and B be x km . Time taken in driving from A to B `t_(1) = ("Distance")/("Speed") = x/30h [because Time = ("Distance")/("Speed")]` Similarly, time taken in returning from B to A . `t_(2)= ("Distance")/("Speed") = x/20h` Average speed = `("Total distance")/("Total time")=(x + x )/(t_(1)+t_(2)` `(x+x)/(x/30+x/20)=(2x)/((2x+3x)/(60))` `(2x xx 60)/(5x)=2xx12kmh^(-1)` Hence, average speed of a motorcycilst is `24 kmh^(-1)`
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