A truck of mass `M` is moved under a force `F`. If the truck is then loaded with an object equal to the mass of the truck and the driving force is halved, then how does the acceleration change?

Explanation

Let, initial mass, `m_(1)=M`
initial force, `F_(1)=F`
According to the question law, new mass, `m_(2)=M+M=2M`
and new force, `F_(2)=(F)/(2)`
From Newton's second law, F=ma
`Rightarrow= a(F)/(m)`
Change in acceleration
`(a_(1))/(a_(2))=(F_(1))/(F_(2))xx(m_(2))/(m_(1))xx(2M)/(M)=(2F)/(F)xx(2m)/(m)=4`
`(a_(1))/(a_(2))=4 Rightarrow 4a_(2)=a_(1)`
`Rightarrow a_(2)=(a_(1))/(4)=(1)/(4)xxa_(1)`
Hence, the new acceleration will be one forth of previous acceleration.