The value of acceleration due to gravity...

The value of acceleration due to gravity

Is same on equator and poles

Is least on poles

Is least on equator

Increases from pole to equator

Text Solution

Verified by Experts

The correct Answer is:

It is least at the equator and and maximum at the poles due to rotation of earth

i.e., it is given by
`g'=g-omega^(2)R sintheta`
At poles `theta=0`, So g maximum
At equator `theta=90^(@)`, So g maximum

Topper's Solved these Questions

FORCE AND LAW OF MOTION
NCERT EXEMPLAR|Exercise Force And Law Of Motion|20 Videos
MOTION
NCERT EXEMPLAR|Exercise Short Answer Type Questions|1 Videos

Similar Questions

Explore conceptually related problems

By considering earth to be non spherical. STATEMENT -1 : As one moves from equator to the pole of earth, the value of acceleration due to gravity increases. and STATEMENT -2 : If earth stops rotating about its own axis, the value of acceleration due to gravity will be same at pole and at equator.

The ratio between the values of acceleration due to gravity at a height 1 //km above and at a depth of 1 km below the Earth’s surface is (radius of Earth is R)

A small steel ball of mass m and radius r is falling under gravity through a viscous liquid of coefficient of viscosity eta . If g is the value of acceleration due to gravity. Then the terminal velocity of the ball is proportional to (ignore buoyancy)

As we go from pole to the equator, the effective value of acceleration due to gravity decreases due to

What is depth at which value of acceleration due to gravity becomes 1/n times value that at surface of earth

The depth at which the effective value of acceleration due to gravity is g/4 is (R=radius of the earth)

Assertion : The time period of a freely falling pendulum is infinite. Reason : The effective value of acceleration due to gravity becomes zero.

Choose the correct alternative :The effect of rotation on the effective value of acceleration due to gravity is greatest at the equator/poles.

Acceleration due to gravity at earth's surface if 'g' m//s^(2) . Find the effective value of acceleration due to gravity at a height of 32 km from sea level : (R_(e)=6400 km)

Assertion (A): At pole value of acceleration due to gravity (g) is greater than that of equator. Reason (R) : Earth rotates on its axis in addition to revolving round the sun.

NCERT EXEMPLAR-GRAVITATION-Gravitation

Two object of different masses falling freely near the surface of moon...
Text Solution
|
The value of acceleration due to gravity
Text Solution
|
The gravitational force between two object is F. It masses of both obj...
Text Solution
|
A boy is whirling a stone tied with a string in a horizontal circular ...
Text Solution
|
An object is put one by one in three liquids having different densitie...
Text Solution
|
In the relation F=G M m//d^(2), the quantity G
Text Solution
|
Law of gravitation gives the gravitational force between
Text Solution
|
The value of quantity of G in the law of gravitation
Text Solution
|
Two particles are placed at some distance. If the mass of each of the ...
Text Solution
|
The atmosphere is held to the earth by
Text Solution
|
The force of attraction between two unit point masses separted by a un...
Text Solution
|
The weight of an object at the centre of the earth of radius R is
Text Solution
|
An object weighs 10 N in air. When immessed fully in liquid, it weighs...
Text Solution
|
A brick stands on a box having 60 cm length, 40 cm breadth and 20 cm w...
Text Solution
|
An apple falls from a tree because of gravitational between the earth ...
Text Solution
|
What is the source of centripetal force that a planet requires to revo...
Text Solution
|
On the earth, a stone is thrown from a height in a direction parallel ...
Text Solution
|
Suppose gravity of earth suddenly become zero, then in which direction...
Text Solution
|
Identical packets are dropped from two areoplanes, one above the equat...
Text Solution
|
The weight of any person on the moon is about 1//6 times that on the ...
Text Solution
|