The weight of an object at the centre of the earth of radius R is

Options

A. zero
B. infinite
C. R times the weight at the surface of the earth
D. `1//R^(2)` times the weight at the surface of the earth

Answer

A

Explanation

The weight of an object, w = mg
At the centre of the earth, acceleration due to gravity g zero. And is given by `g^(')=g(1-(h)/(R))` where h = distance from surface of the earth to centre of the earth and at
`centre(h=R)i.e.," "g^(')=0`.
`So," "w=mxx0=0`