On the earth, a stone is thrown from a height in a direction parallel to the earth's surfaces while another stone is simultaneously dropped from the same height. Which stone whould reach the ground first and why ?

Explanation

Tme taken by both atone is given second equation of motion `s=ut+1//2at^(2)`
`As" "U_(y)=O,SO,S=1//2at^(2)`
`and here" "s=h`
Where, m = Initial velocity in y-axis
a = g accelaration due to gravity
t = time displacement to time
`So," "h=1//2"gt"^(2)`
`" "t=sqrt((2h)/(g))`
Therefore, it we drop down a stone form a height (h) and at same time throw another stone in horizontal direction, then both the stone strike the earth simultaneously at different piaces.