A rocket is moving up with a velocity `upsilon` if the velocity of this rocket is suddenly tripled, what will be the ratio of two kinetic energies ?

Explanation

Given, `v_(1)=vand v_(2)=3v`
`:."Kinetic energy of rocket"(K)=(1)/(2)mv^(2)`
The ratio of two kinetic energies, `(K_(1))/(K_(2))=(v_(1)^(2))/(v_(2)^(2))(putv_(2)=3vandv_(1)=v)`
we get `=(v^(2))/((3v)^(2))=(v^(2))/(gv^(2))rArr(K_(1))/(K_(2))=(1)/(9)`
Thus, the ratio of two kinetic energies `K_(1):K_(2)=1:9`