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If an electric iron of 1200 W is used fo...

If an electric iron of 1200 W is used for 30 minutes everyday, find electric energy consumed in the month of Aprill.

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Given, power of electric iron = 1200 W
`"Time"(t)=30min=30xx60s=1800s`
We know that, `"Power"=("energy")/("time")`
`1200=(E)/(30xx60)`
`E=1200xx30xx60=21.6xx10^(5)J`
`"Energy used in one day"=21.6xx10^(5)J`
`"Energy used in 30 day"=21.6xx10^(5)xx30=6.4xx10^(7)J`
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