Which of the following has maximum number of atoms?

Options

A. `18` g of `H_(2)O`
B. `18` g of `O_(2)`
C. `18` g of `CO_(2)`
D. `18` g of `CH_(4)`

Answer

D

Explanation

option d) is the correct answer, i.e., 18g of `CH_(4)` has maximum number of atoms.
a) Number of atoms in 18g of `H_(2)O = 18/18 xx 6.022 xx 10^(23) xx 3`
`=18.066 xx 10^(23)=1.8066 xx 10^(24)`
b) Number of atoms in 18g of `O_(2) = 18/32 xx 6.022 xx 10^(23) xx 2`
`=3.387 xx 10^(23) xx 2=6.774 xx 10^(23)`
c) Number of atoms in 18g of `CO_(2) = 18/44 xx 6.022 x 10^(23) xx 3=7.390 xx 10^(23)`
d) Number of atoms in 18g of `CH_(4) = 18/16 xx 6.022 xx 10^(23) xx 5=3.387 xx 10^(24)`
Thus, 18g of `CH_(4)` contains the maximum number of atoms.