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An alkyl halide C(5)H(11) (A) reacts wit...

An alkyl halide `C_(5)H_(11)` (A) reacts with ethanolic KOH to give an alkene 'B' which reacts with `Br_(2)` to give a compound 'C' which on dehydromination gives an alkyne 'D' . On treatment with sodium metal in liquid ammonia one mole of 'D' give one mole of the sodium salt of 'D' and half a mole of hydrogen gas . Complete hydrogenation of 'D' yields a straight chain alkane. Identify A, B, C and D . Give the the reactions involved.

Text Solution

AI Generated Solution

To solve the problem, we will identify the compounds A, B, C, and D step by step, along with the reactions involved. ### Step 1: Identify Compound A Given that A is an alkyl halide with the formula C5H11Br, we can deduce that it is a bromoalkane. A common structure for this compound could be 1-bromopentane (Br-CH2-CH2-CH2-CH3). ### Step 2: Reaction of A with Ethanolic KOH When 1-bromopentane (A) reacts with ethanolic KOH, an elimination reaction occurs, leading to the formation of an alkene (B) through dehydrohalogenation. The reaction can be represented as follows: ...
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Knowledge Check

  • Benzamide is reacted with sodium metal in ethanol gives

    A
    Aniline
    B
    Benzyl amine
    C
    benzoic acid
    D
    Benzaldehyde

  • Hydrogenation of the above compound in the presence of sodium in liquid ammonia gives -

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    B
    An optically inactive compound
    C
    A racemic mixture
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    A diastereomeric mixture

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    A
    `1` mole
    B
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    C
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    D
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