The radius of `Na^(+)` cation is less than that of Na atom. Give reason.

Answer

A

Explanation

When an atom loses an electron to form cation, its radius decreases. In a cation, per electron nuclear forces increases due to increases due to decrease in number of electrons. As a result of this, effective nuclear charge increases and the radius of cation decreases. e.g., ionic radius of `Na^(+)` is smaller than the radius of its parent atom Na.