The graph given below represents the linear equation x+y=0.

Explanation

True
If the given points `(-1,1) " and " (-3,3)` lie on the linear equation x+y=0, then both points will satisfy the equation.
So, at point `(-1,1)` we put x=-1 and y=1 in LHS of the given equation, we get
LHS`=x+y= - 1+1=0`=RHS
Again, at point `(-3,3)` put x=-3 and y=3 in LHS of the given equation, we get
LHS `=x+y=-3+3=0`= RHS
Hence, `(-1,1) " and " (-3,3)` both satisfy the given linear equation x+y=0.