Chloromethane on treatment with excess of ammonia yields mainly

Options

A.
B. N-Methylmethaneamine(`CH_(3)-NH-CH_(3)`)
C. methanamine`(CH_(3)NH_(2))`
D. mixture containing all these in equal proportion

Explanation

To solve the question, "Chloromethane on treatment with excess of ammonia yields mainly," we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactant we have is chloromethane, which is represented as CH₃Cl.
- The other reactant is ammonia, which is represented as NH₃. We are told that ammonia is in excess.

2. **Understand the Reaction**:
- Chloromethane (CH₃Cl) can react with ammonia (NH₃) in a nucleophilic substitution reaction. In this reaction, the chlorine atom in chloromethane is replaced by an amino group from ammonia.

3. **Reaction Mechanism**:
- The reaction can be represented as:
\[ \text{CH}_3\text{Cl} + \text{NH}_3 \rightarrow \text{CH}_3\text{NH}_2 + \text{HCl} \]
- Here, the chlorine atom (Cl) is replaced by an amine group (NH₂), resulting in the formation of methanamine (CH₃NH₂) and hydrochloric acid (HCl) as a byproduct.

4. **Consider the Excess of Ammonia**:
- Since ammonia is in excess, it will favor the formation of the primary amine, which is methanamine (CH₃NH₂). If ammonia were not in excess, we could potentially form secondary and tertiary amines as well, but that is not the case here.

5. **Identify the Main Product**:
- The main product formed from the reaction of chloromethane with excess ammonia is methanamine (CH₃NH₂).

6. **Conclusion**:
- Therefore, the answer to the question is that chloromethane on treatment with excess ammonia yields mainly methanamine (CH₃NH₂).

### Final Answer:
The correct answer is **methanamine (CH₃NH₂)**.

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