Which of the following are secondary bromides ?

Options

A. `(CH_(3))_(2)CHBr`
B. `(CH_(3))_(3)CCH_(2)Br`
C. `CH_(3)CH(Br)CH_(2)CH_(3)`
D. `(CH_(3))_(2)CBrCH_(2)CH_(3)`

Answer

A, C

Explanation

`(a) H_(3)C-underset(CH_(3))underset(|)"CH"-Br` (b)`H_(3)C-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-CH_(2)Br`
(c) `H_(3)C-underset(Br)underset(|)"CH"-CH_(2)-CH_(3)` (d) `H_(3)C-underset(CH_(3))underset(|)overset(Br)overset(|)C-CH_(2)CH_(3)`
Secondary bromides are those compounds in which `alpha`-carbone (i.e, carbon bonded to bromine) is further bonded to two alkyl groups.
In compound (a) and (c) `alpha`-carbon is bonded to two alkyl groups thats why it is secondary bromide but in compound (b) it is bonded to one alkyl group and it is primary bromide, In compound (c) it is bonded to three alkyl groups and it is tertiary alkyl halide.