Alkyl halides are prepared from alcohols by treating with

Options

A. `HCl+ZnCl_(2)`
B. Red P+`Br_(2)`
C. `H_(2)SO_(4)`+Kl
D. All of these

Answer

A, B

Explanation

(a) Alcohol when treated with `HCI + ZnCl_(2)` then alkyl halide is formed.
`ROH+Hcloverset(ZnCl_(2))tounderset(("Alkyl halide"))(RCl+H_(2)O)`
(b) Alcohol when treated with red P and `X_(2)` then product is alkyl halide.
`R-Ohoverset("Red P//"Br_(2))tounderset((" Alkyl halide"))(R-X)`
(c) Alcohols when treated with `H_(2)SO_(4)` and KI then `H_(2)SO_(4)`, oxidises Kl to `I_(2)` and does not produce Hl. therefore, alkylide does not form if the alcohols are treated with `H_(2)SO_(4)+KI`.