Identify the product A and B formed in the following reaction
`CH_(3)-CH_(2)-CH=CH-CH_(3)+HCl toA+B`

Explanation

In the given reaction, addition occur and the following two products (A and B) are possible
`H_(3)C-CH_(2)-CH=CH-CH_(3)+Hcltounderset((2-"chloropentane"))(CH_(3)-CH_(2)-CH_(2)-underset(Cl)underset(|)"CH"-CH_(3))`
`underset((3-"chloropentane"))(+CH_(3)-CH_(2)-underset(Cl)underset(|)"CH"-CH_(2)-CH_(3))`
Further the carbocation formed from compound (A) is slightly less stable than carbocation leading to the formation of compound (B) therefore the amount of 2-chloropentane (B) will be slightly more than thhat of 3-chloropentane (A).