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Higher oxidation state of manganese in f...

Higher oxidation state of manganese in fluoride is `+4 (MnF_(4))` but highest oxidation state in oxides is `+7(Mn_(2)O_(7))` because

A

fluorine is more electronegative than oxygen

B

fluorine does not posses d orbitals

C

fluorine stabilises lower oxidation state

D

in covalent compounds, fluorine can form single bond only while oxygen forms double bond

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The correct Answer is:
D

Highest oxidation state of manganese in fluoride is `+4(MnF_(4))` but highest oxidation state in oxides is `+7(Mn_(2)O_(7))`. The reason is that in covalent compounds fluorine can form single bond while oxygen forms double bond.
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