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Although Zr belongs to 4d and Hf belongs...

Although Zr belongs to 4d and Hf belongs to 5d transition series but it is quite difficult to separate them, Why?

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Separation of Zr and Hf are quite difficult because of lanthanoid contraction. Due to lanthanoid contration, they have almost same size (Zr = 160 pm and Hf = 159 pm) and thus, similar chemical properties. That's why it is very difficult to separate them by chemical methods.
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NCERT EXEMPLAR-D AND F-BLOCK ELEMENTS-D And F-Block Elements
  1. Although Cr^(3+) and Co^(2+) ions have same number of unpaired electro...

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  2. Ionisation enthalpies of Ce, Pr and Nd are higher than Th, Pa and U. W...

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  3. Although Zr belongs to 4d and Hf belongs to 5d transition series but i...

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  4. Cerium shows oxidation state of +4 because

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  5. Explain why does colour of KMnO(4) disappear when oxalic acid is added...

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  6. When orange solution containing Cr(2)O(7)^(2-) ion is treated with an ...

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  7. A solution of KMnO(4) on reduction yields either a colourless solution...

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  8. The second and third rows of transition elements resemble each other m...

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  9. E^(Theta) of Cu is +0.34V while that of Zn is -0.76 V. Explain.

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  10. The halides of transition elements become more covalent with increasin...

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  11. While filling up of electrons in the atomic orbitals, the 4s orbital i...

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  12. Reactivity of transition elements decreases almost regularly from Se t...

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  13. Match the catalyst given in Column I with the processes given in Colum...

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  14. Match the compounds/elements given in Column I with uses given in Colu...

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  15. Match the properties given in Column I with the metals given in Column...

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  16. Match the statements given in Column I with the oxidation states given...

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  17. Match the solutions given in Column I and the colours given in Column ...

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  18. Match the property given in Column I with the element given in Column ...

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  19. Match the properties given in Column I with the metals given in Column...

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  20. Assertion (A) Cu^(2+) iodine is not known. Reason (R ) Cu^(2+) oxidi...

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