A mass of 2kg is attached to the spring of spring constant `50Nm^(-1)`. The block is pulled to a distance of 5 cm from its equilibrium position at `x=0` on a horizontal frictionless surface from rest at t=0. Write the expression for its displacement at anytime t.

Explanation

To solve the problem, we need to derive the expression for the displacement of a mass attached to a spring at any time \( t \). Here are the steps:

### Step 1: Identify the given values
- Mass \( m = 2 \, \text{kg} \)
- Spring constant \( k = 50 \, \text{N/m} \)
- Initial displacement \( x_0 = 5 \, \text{cm} = 0.05 \, \text{m} \)
- The system is released from rest, so the initial velocity \( v_0 = 0 \).

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